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5g^2=72
We move all terms to the left:
5g^2-(72)=0
a = 5; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·5·(-72)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*5}=\frac{0-12\sqrt{10}}{10} =-\frac{12\sqrt{10}}{10} =-\frac{6\sqrt{10}}{5} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*5}=\frac{0+12\sqrt{10}}{10} =\frac{12\sqrt{10}}{10} =\frac{6\sqrt{10}}{5} $
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